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1 of 5
Higher
Non-calculator
R15 Instantaneous and average rates of change from curves
Question 1 · 5 marks
Spec and skills
Paper scope: Paper 1: non-calculator practice
Spec R15
Spec A15
Original practice question
Answer and supported method checks
A ball is thrown upwards. Its height,
h
h
h
metres, after
t
t
t
seconds is
h
=
20
t
−
5
t
2
h = 20t - 5t^2
h
=
20
t
−
5
t
2
.
(a)
Work out the average rate of change of height between
t
=
1
t = 1
t
=
1
and
t
=
3
t = 3
t
=
3
.
2 marks