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HigherNon-calculatorR15 Instantaneous and average rates of change from curves

Question 1 · 5 marks

Spec and skills
  • Paper scope: Paper 1: non-calculator practice
  • Spec R15
  • Spec A15
  • Original practice question
  • Answer and supported method checks
A ball is thrown upwards. Its height, hh metres, after tt seconds is h=20t−5t2h = 20t - 5t^2.
(a)
Work out the average rate of change of height between t=1t = 1 and t=3t = 3.
2 marks