Cumulative frequency is a running total. Plot each total at the upper end of its class and join with a smooth curve. Read the median at half the total, and the quartiles at a quarter and three quarters.
Add up the frequencies as you go.
Plot at the upper class boundaries.
Interquartile range = upper quartile − lower quartile.
Watch out Plot at the end of each class, not the middle.
See it worked
Worked exampleNon-calculator·2 marks
The table shows information about the marks of 80 students in a test.
Grouped frequency table of marks for 80 students. 0 < m ≤ 20: 4. 20 < m ≤ 40: 10. 40 < m ≤ 60: 26. 60 < m ≤ 80: 30. 80 < m ≤ 100: 10.
Mark (m)
Frequency
0 < m ≤ 20
4
20 < m ≤ 40
10
40 < m ≤ 60
26
60 < m ≤ 80
30
80 < m ≤ 100
10
(a) Work out the cumulative frequency for marks up to 60.
(b) Write down the coordinates of the point plotted for the class 40<m≤60 on a cumulative frequency graph.
(a) 4+10+26=40.
(b) Cumulative frequencies are plotted at the upper bound of each class.
Answer (a) 40; (b) (60,40)
Your turn
Question 1Calculator allowed·2 marks
The cumulative frequency graph shows information about the waiting times of 80 people.
Use the graph to find an estimate for the number of people who waited more than 25 minutes.
051015202530354020406080Waiting time (minutes)Cumulative frequency
Question 2Calculator allowed·4 marks
The cumulative frequency graph shows information about 120 processing times.
Use cumulative frequencies 30 and 90 for the lower and upper quartiles.
A new process changes every time according to u=1.2t+3.
Use the graph to estimate the interquartile range of the new times. Give your answer to 1 decimal place.
051015202530354020406080100120Time (t seconds)Cumulative frequency
Question 3Non-calculator·4 marks
The cumulative frequency graph shows information about the heights of 60 plants.
(a) Use the graph to find an estimate for the median height.
(b) Use the graph to estimate the number of plants taller than 35 cm.
05101520253035404550102030405060Height (cm)Cumulative frequency
In past papers
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