GCSE Maths revision · Higher: number and algebra

Exponential and trig graphs

Higher only

The idea

An exponential graph y=axy = a^x (with a>1a > 1) passes through (0,1)(0, 1) and climbs ever more steeply. y=sin⁡xy = \sin x and y=cos⁡xy = \cos x repeat every 360∘360^\circ between −1-1 and 11; y=tan⁡xy = \tan x repeats every 180∘180^\circ.

  1. Plot key points: (0,1)(0, 1) for exponentials; 0∘0^\circ, 90∘90^\circ, 180∘180^\circ, 270∘270^\circ, 360∘360^\circ for trig.
  2. y=tan⁡xy = \tan x has asymptotes at 90∘90^\circ and 270∘270^\circ.
  3. Use the symmetry of the graph to find other solutions.

Watch out sin⁡\sin and cos⁡\cos never go above 11 or below −1-1.

See it worked

Worked exampleCalculator allowed2 marks

A model gives the mass of a culture at times 0, 1, 2, 3 and 4 hours as 80, 120, 180, 270 and 405 grams respectively. The plotted points are joined by straight segments. Use this graph model to estimate when the mass reaches 300 grams. Give your answer to 1 decimal place.

  1.  3+(300−270)/(405−270)3+(300-270)/(405-270)
  2. 300 grams lies between the points (3, 270) and (4, 405).
  3. The increase of 30 grams is 30/(405 −- 270) = 2/9 of this one-hour segment.
  4. The estimate is 3 + 2/9 = 3.222… hours, or 3.2 hours to 1 decimal place.

Answer 3.23.2 hours

Your turn

Question 1Calculator allowed2 marks

Find all values of x between 0∘0^\circ and 360∘360^\circ, inclusive, for which sin x = 1/2.

Question 2Non-calculator5 marks

y=2sin⁡(x−60)y=2\sin(x-60) for 60∘≤x≤420∘60^\circ\le x\le 420^\circ.

(a) Find all x for which y = 1.

(b) Find the maximum value of y.

Question 3Non-calculator5 marks

sin⁡40∘=0.643\sin 40^{\circ} = 0.643, correct to 3 decimal places.

(a) Find another angle between 0∘0^{\circ} and 360∘360^{\circ} whose sine is 0.6430.643.

(b) Find the angle between 180∘180^{\circ} and 270∘270^{\circ} whose sine is −0.643-0.643.

(c) Find the angle xx between 0∘0^{\circ} and 90∘90^{\circ} with cos⁡x=0.643\cos x = 0.643.

In past papers

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