Worksheets · Foundation and Higher

Angles at points, lines and parallel lines

8 exam-style questions, grades 2 to 6. Worked solutions and the marks are on the last page.

  1. Question 1Non-calculator · 2 marks

    (a) Three adjacent angles on one side of a straight line are 41∘41^\circ, 76∘76^\circ and x∘.x^\circ. Work out x. (2)

  2. Question 2Non-calculator · 3 marks

    Two straight lines cross. One of the angles formed is 128∘128^\circ. The angle opposite it is aa and an angle next to it is bb.

    (a) Write down the size of angle aa. (1)

    (b) Choose the reason for your answer to part (a). (1)

    1. Opposite angles are equal
    2. Angles on a straight line add up to 180 degrees
    3. Vertically opposite angles are equal

    (c) Work out the size of angle bb. (1)

  3. Question 3Non-calculator · 3 marks

    Two parallel horizontal lines are cut by a transversal. At the upper intersection an acute angle is 45∘45^\circ.

    (a) Find the obtuse angle adjacent to that angle on a straight line. (2)

    (b) Give the size of the corresponding acute angle at the lower intersection, with a reason. (1)

  4. Question 4Non-calculator · 5 marks

    Four angles around a point are x∘x^\circ, (2x+10)∘(2x+10)^\circ, (3x)∘(3x)^\circ and (4x−10)∘(4x-10)^\circ.

    (a) Find x. (3)

    (b) Find the largest of the four angles. (2)

  5. Question 5Non-calculator · 4 marks

    Two co-interior angles between parallel lines are (3x+4)∘(3x+4)^\circ and (5x+4)∘(5x+4)^\circ.

    (a) Find x. (2)

    (b) Find the smaller angle. (2)

  6. Question 6Non-calculator · 5 marks

    AB and CD are parallel lines. A transversal meets AB at P and CD at Q. Angle APQ = 3y∘3y^\circ and angle PQD = (y+40)∘(y + 40)^\circ. These two angles are alternate angles.

    (a) Find y. (2)

    (b) Work out the size of angle APQ. (2)

    (c) Give the geometric reason used in part (a). (1)

  7. Question 7Non-calculator · 4 marks

    Two straight lines cross at O. One angle at O is (4x+12)∘(4x + 12)^\circ and the angle vertically opposite it is (6x−20)∘(6x - 20)^\circ.

    (a) Find x. (2)

    (b) Find the size of each of the other two angles at O. (2)

  8. Question 8Non-calculator · 4 marks

    A straight line EFEF crosses the lines ABAB and CDCD at GG and HH. At GG the angles on one side of EFEF are (5x−20)∘(5x - 20)^\circ and (3x+8)∘(3x + 8)^\circ, and they lie on the straight line ABAB. At HH, the angle corresponding to the (3x+8)∘(3x + 8)^\circ angle is (2x+30)∘(2x + 30)^\circ.

    (a) Is ABAB parallel to CDCD? You must show how you get your answer. (4)

    1. AB is not parallel to CD
    2. AB is parallel to CD

Worked solutions and marks

Question 1

(a) 6363°

  1. 180−41−76180-41-76
  2. Angles on a straight line add to 180∘.180^\circ.
  3. x = 180 −- 41 −- 76 = 63.
  • P1 Establishing 180−41−76180-41-76 or an equivalent valid method.
  • A1 Correct answer: 6363°

Question 2

(a) 128∘128^\circ

  1. aa is vertically opposite the 128∘128^\circ angle, so it is equal to it.
  • B1 Correct answer: 128∘128^\circ.

(b) Vertically opposite angles are equal.

  1. Two crossing straight lines make two pairs of vertically opposite angles, and each pair is equal.
  • C1 Choosing "vertically opposite angles are equal".

(c) 52∘52^\circ

  1. Angles on a straight line add up to 180∘180^\circ, so b=180−128=52∘b = 180 - 128 = 52^\circ.
  • B1 Correct answer: 52∘52^\circ.

Question 3

(a) 135135°

  1. Adjacent angles on a straight line sum to 180 degrees.
    180−45180-45
  2. Therefore 135135°.
  • M1 Adjacent angles on a straight line sum to 180 degrees.
  • A1 Correct answer: 135135°

(b) It is 45∘45^\circ because corresponding angles between parallel lines are equal.

  1. It is 45∘45^\circ because corresponding angles between parallel lines are equal.
  • C1 Correct conclusion with supporting reasoning: It is 45∘45^\circ because corresponding angles between parallel lines are equal.

Question 4

(a) x=36x = 36

  1. The four angles form one full turn.
    x+2x+10+3x+4x−10=360x+2x+10+3x+4x-10=360
  2. Collect the coefficients before dividing.
    10x=36010x=360
  3. Therefore x=36x = 36.
  • M1 The four angles form one full turn.
  • M1 Collect the coefficients before dividing.
  • A1 Correct answer: x=36x = 36

(b) 134134°

  1. Substitute x into the largest coefficient expression and compare.
    4×(36)−104\times (36)-10
  2. Therefore 134134°.
  • M1 Substitute x into the largest coefficient expression and compare.
  • A1 Correct answer: 134134°

Question 5

(a) 432\frac{43}{2}

  1. Co-interior angles between parallel lines are supplementary.
    3x+4+5x+4=1803x+4+5x+4=180
  2. Therefore 432\frac{43}{2}.
  • M1 Co-interior angles between parallel lines are supplementary.
  • A1 Correct answer: 432\frac{43}{2}

(b) 68.568.5°

  1. Substitute into the smaller angle expression.
    3×(43/2)+43\times (43/2)+4
  2. Therefore 68.568.5°.
  • M1 Substitute into the smaller angle expression.
  • A1 Correct answer: 68.568.5°

Question 6

(a) 2020

  1. Alternate angles are equal, so form an equation.
    3y=y+403y=y+40
  2. Therefore 2020.
  • M1 Alternate angles are equal, so form an equation.
  • A1 Correct answer: 2020

(b) 6060°

  1. Substitute y into 3y.
    3×203\times 20
  2. Therefore 6060°.
  • M1 Substitute y into 3y.
  • A1 Correct answer: 6060°

(c) Alternate angles between parallel lines are equal.

  1. Alternate angles between parallel lines are equal.
  • C1 Correct conclusion with supporting reasoning: Alternate angles between parallel lines are equal.

Question 7

(a) 1616

  1. Vertically opposite angles are equal.
    4x+12=6x−204x+12=6x-20
  2. Therefore 1616.
  • M1 Vertically opposite angles are equal.
  • A1 Correct answer: 1616

(b) 104104°

  1. The other angles lie on a straight line with a 76° angle.
    180−76180-76
  2. Therefore 104104°.
  • M1 The other angles lie on a straight line with a 76° angle.
  • A1 Correct answer: 104104°

Question 8

(a) No: x=24x = 24, so the corresponding angles are 80∘80^\circ and 78∘78^\circ, which are not equal.

  1. Angles on a straight line add up to 180∘180^\circ.
    (5x−20)+(3x+8)=180(5x - 20) + (3x + 8) = 180
  2. Solve.
    8x−12=180⇒x=248x - 12 = 180 \quad\Rightarrow\quad x = 24
  3. At GG the angle is 3(24)+8=80∘3(24) + 8 = 80^\circ. At HH the corresponding angle is 2(24)+30=78∘2(24) + 30 = 78^\circ.
  4. Corresponding angles on parallel lines are equal. 80∘≠78∘80^\circ \ne 78^\circ, so ABAB is not parallel to CDCD.
  • P1 Forming the equation from angles on a straight line.
  • P1 Solving to x=24x = 24.
  • P1 Working out both corresponding angles, 80∘80^\circ and 78∘78^\circ.
  • C1 "Not parallel", because the corresponding angles (80∘80^\circ and 78∘78^\circ) are not equal.

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Angles at points, lines and parallel lines

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Independent practice for Pearson Edexcel GCSE Mathematics (1MA1), not endorsed by Pearson.

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