GCSE Combined Science revision · Physics: forces, waves and magnetism

Forces and elasticity

The idea

Stretching, bending or compressing an object needs more than one force. Elastic deformation means the object returns to its original shape when the forces are removed; inelastic deformation means it does not. For a spring, the extension is directly proportional to the force applied, F = ke, up to the limit of proportionality. The spring constant k is in N/m. If the spring is not inelastically deformed, the work done stretching it is stored as elastic potential energy.

  1. Find the extension: new length − original length.
  2. Use F = ke with e in metres.
  3. Check whether the limit of proportionality has been passed.

Watch out Extension is the increase in length, not the total length.

See it worked

Worked example

A spring 0.20 m long stretches to 0.25 m when a 10 N force is applied. Calculate the spring constant.

  1. Extension = 0.25 − 0.20 = 0.05 m.
  2. k = F ÷ e = 10 ÷ 0.05 = 200 N/m.

Answer 200 N/m

Your turn

Question 1Calculator allowed2 marks

A spring with k = 50 N/m is stretched by 0.08 m. What force is applied, in newtons?

Question 2Calculator allowed1 mark

What is elastic deformation?

Choose one
Question 3Calculator allowed1 mark

Beyond the limit of proportionality, extension and force are:

Choose one

In past papers

38 official questions in 36 papers since 2018. The latest:

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Independent practice for AQA GCSE Combined Science: Trilogy (8464), not endorsed by AQA.

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