How much energy is needed to heat 2.0 kg of water from 20 °C to 70 °C? (c = 4200 J/kg °C)
- Δθ = 70 − 20 = 50 °C.
- ΔE = 2.0 × 4200 × 50 = 420 000 J.
Answer 420 000 J
GCSE Combined Science revision · Physics: energy, electricity, particles and atoms
Internal energy is the total kinetic and potential energy of the particles in a system. Heating raises the temperature or changes the state. Specific heat capacity is the energy needed to raise the temperature of 1 kg by 1 °C: ΔE = mcΔθ. Specific latent heat is the energy needed to change the state of 1 kg with no change in temperature: E = mL. Latent heat of fusion is for melting; of vaporisation is for boiling.
Watch out During a change of state the temperature stays the same: energy is taken in when melting or boiling and released when freezing or condensing.
How much energy is needed to heat 2.0 kg of water from 20 °C to 70 °C? (c = 4200 J/kg °C)
Answer 420 000 J
How much energy, in joules, is needed to melt 0.5 kg of ice? (Specific latent heat of fusion of ice = 334 000 J/kg)
A 0.5 kg metal block is given 9000 J and its temperature rises by 20 °C. What is its specific heat capacity in J/kg °C?
While water is boiling, its temperature:
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