A filament lamp is 5% efficient and an LED is 40% efficient. For 10 J of light, how much electrical energy does each need?
- Input = useful ÷ efficiency.
- Filament: 10 ÷ 0.05 = 200 J. LED: 10 ÷ 0.40 = 25 J.
Answer Filament 200 J, LED 25 J
GCSE Combined Science revision · Physics: energy, electricity, particles and atoms
To increase efficiency, reduce wasted energy transfers: lubricate moving parts, use thermal insulation, streamline vehicles, and use components that heat up less, such as LED lamps instead of filament lamps. Efficiency calculations can be rearranged: useful output = efficiency × total input.
Watch out Higher efficiency means a bigger fraction of the input is useful: the same useful output needs less input.
A filament lamp is 5% efficient and an LED is 40% efficient. For 10 J of light, how much electrical energy does each need?
Answer Filament 200 J, LED 25 J
A machine has a useful output of 300 J and an efficiency of 0.6. What is the total input energy in joules?
Which change improves the efficiency of a house's heating?
Why does streamlining a car improve its efficiency?
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