GCSE Maths revision · Algebra

Identities and showing that

Foundation and Higher

The idea

An identity is true for every value of the letter, written with ≡\equiv. To show one, expand and simplify one side until it matches the other.

  1. Start from one side, usually the more complicated one.
  2. Expand and collect like terms, one line at a time.
  3. Match coefficients: if ax+6≡4x+2bax + 6 \equiv 4x + 2b, then a=4a = 4 and b=3b = 3.

Watch out Testing one value does not prove an identity; it can only disprove it.

See it worked

Worked exampleNon-calculator2 marks

Ellie says, "x+x+xx + x + x is the same as x3x^3."

(a) Is Ellie correct? Give a reason for your answer.

(b) Simplify x+x+xx + x + x

  1. (a) x+x+x=3xx + x + x = 3x, which is three lots of xx added. x3x^3 is three xx's multiplied.
  2. For example, when x=2x = 2: 3x=63x = 6 but x3=8x^3 = 8.
  3. (b) Three lots of xx: 3x3x.

Answer (a) No: x+x+x=3xx + x + x = 3x, but x3=x×x×xx^3 = x \times x \times x.; (b) 3x3x

Your turn

Question 1Calculator allowed1 mark

Which statement is an identity?

Choose one
Question 2Non-calculator4 marks

Decide whether each statement is an identity or an equation.

(a) (x+1)2−x2=2x+1(x + 1)^2 - x^2 = 2x + 1

(b) 4(x−2)=2(x+3)4(x - 2) = 2(x + 3)

Write your answer, then show the working
  1. (a) Expand the square and simplify the left side. (x+1)2−x2=2x+1(x+1)^{2}-x^{2}=2x+1
  2. An identity: expanding gives x2 + 2x + 1 - x2 = 2x + 1 for every value of x.
  3. (b) Expand both sides and solve. 4x−8=2x+64x-8=2x+6
  4. An equation: it is true only when x = 7.

Answer (a) An identity: expanding gives x2 + 2x + 1 - x2 = 2x + 1 for every value of x.; (b) An equation: it is true only when x = 7.

Question 3Calculator allowed4 marks

The identity (2x + a)(x −- 3) + b ≡\equiv 2x22x^{2} + x + 7 is true for every x. Find a + b.

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